Solution of $\triangledown ^{2} T = 0$ in a square domain ($0 < x< 1$ and $0 < y< 1$) with boundary conditions: $T \left ( x,0 \right ) = x; T \left ( 0,y \right ) = y; T\left ( x,1 \right ) = 1 + x; T\left ( 1,y \right )= 1 +y$ is $T \left ( x,y \right ) = x - xy +y$ $T \left ( x,y \right ) = x + y$ $T \left ( x,y \right ) = -x + y$ $T \left ( x,y \right ) = x + xy + y$

asked
Feb 15
in Others
Arjun
27.4k points