0 0 votes The limit $$p = \lim_{x\rightarrow \pi} \left ( \frac{x^{2} + \alpha x + 2 \pi^{2}}{x - \pi + 2 \sin x } \right )$$ has a finite value for a real $\alpha$. The value of $\alpha$ and the corresponding limit $p$ are $\alpha = -3 \pi$ ,and $p= \pi$ $\alpha = -2 \pi$ ,and $p= 2\pi$ $\alpha = \pi$ ,and $p= \pi$ $\alpha = 2 \pi$ ,and $p=3 \pi$ Calculus gateme-2022-set1 calculus numerical-answers + – ♦Arjun 563 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.