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A right-angled cone (with base radius $5$ cm and height $12$ cm), as shown in the figure below, is rolled on the ground keeping the point $P$ fixed until the point $Q$ (at the base of the cone, as shown) touches the ground again.

By what angle (in radians) about $P$ does the cone travel?

  1. $\dfrac{5\pi}{12} \\$
  2. $\dfrac{5\pi}{24} \\$
  3. $\dfrac{24\pi}{5} \\$
  4. $\dfrac{10\pi}{13}$

3 Answers

Best answer
10 10 votes
Point $Q$ will touch again, when cone will roll around $P$ and will travel arc length of $2\pi r$

So, arc length made by cone $= 2 \pi r = 10\pi $ cm

If the cone rotates one round around point $P$ it will cover perimeter of length $2 \pi l$ cm

where, $l = \sqrt{h^2+r^2} = 13$ cm

So, perimeter of one rotation $= 26 \pi$ cm

Thus, the angle(in radian) which cone makes $= \frac{10\pi}{26\pi}\times 360\times \frac{\pi}{180} = \frac{10\pi}{13}$

Correct Answer: $D$
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6 6 votes

Base radius = 5cm, Height = 12m. So Slant Height = $\sqrt{5^{2}+12^{2}}$ = 13cm.

We open it now. I appears as an arc if opened. Radius of the arc = Slant Height of the cone = 13cm.

Length of the arc = Circumfernce of the cone = 2*π*5 = 10πcm

Now, when, length of arc is 2*π*13, angle subtended is 2π.

So, angle subtended when length of arc is 10π = $\frac{2π}{26π} * 10π$ = $\frac{10π}{13}$

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The Question is asking angle about P that the cone rolls.
When the cone is revolving around a fixed point P , it traces a circle.
The radius of the circle is Slant height of the cone and the arc length covered is the perimeter of the base of the cone.
We are asked when the cone completes one full rotation , what will be the angle formed at the center.

 


arc length = radius  X angle(in radian)




Here,
radius = Slant height
arc lenght = perimeter of base circle of cone
slant height = 13 (apply pythagoras theorem)
perimeter of base circle = 10pi
therefore angle = 10pi/13

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