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2 Answers

Best answer
12 12 votes

Given that:

$$\begin{array}{|l|l|}\hline \textbf{Employees} & \textbf{Salaries}\\\hline 45 & 20,000 \\\hline 25 & 30,000 \\\hline 20 & 40,000 \\\hline 8 & 60,000 \\\hline 2 & 150,000\\\hline \end{array}$$

The Median 

$(1)$ If the total number of numbers$(n)$ is an odd number, then the formula is given below (the numbers are assumed to be in ascending order)$:$

$$\text{Median}=\left(\dfrac{n+1}{2}\right)^{th}\text{term}$$

$(2)$ If the total number of numbers(n) is an even number, then the formula is given below$:$

$$\text{Median}=\dfrac{\left(\dfrac{n}{2}\right)^{th}\text{term}+\left(\dfrac{n}{2}+1\right)^{th}\text{term}}{2}$$

Here, $n=100$

$\text{Median}=\dfrac{\left(\dfrac{100}{2}\right)^{th}\text{term}+\left(\dfrac{100}{2}+1\right)^{th}\text{term}}{2}$

$\text{Median}=\dfrac{\left(50\right)^{th} \ \text{term}+\left(51\right)^{th} \ \text{term}}{2}$

$\text{Median}=\dfrac{30,000+30,000}{2}=30,000 $

So, the correct answer is $(B).$

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1 1 vote
my approach was arrange oin increasing order like 2,8,20,25,45

 

then here middle value is 20 which earn rs 40000 per month so dont do this mistake

Many people will think like this
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