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GATE2016-3-3
Arjun
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Differential Equations
Feb 24, 2017
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Mar 5, 2021
by
Lakshman Patel RJIT
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Solutions of Laplace’s equation having continuous second-order partial derivatives are called
biharmonic functions
harmonic functions
conjugate harmonic functions
error functions
gateme-2016-set3
differential-equations
laplace-transforms
Arjun
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Differential Equations
Feb 24, 2017
recategorized
Mar 5, 2021
by
Lakshman Patel RJIT
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Arjun
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Arjun
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Differential Equations
Feb 24, 2017
GATE2016-2-3
Laplace transform of $\cos( \omega t)$ is $\dfrac{s}{s^2+\omega ^2} \\$ $\dfrac{\omega }{s^2+\omega ^2} \\$ $\dfrac{s}{s^2-\omega ^2} \\$ $\dfrac{\omega }{s^2-\omega ^2}$
Arjun
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Differential Equations
Feb 24, 2017
by
Arjun
27.4k
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gateme-2016-set2
differential-equations
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Arjun
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Differential Equations
Feb 24, 2017
GATE2016-1-2
If $f(t)$ is a function defined for all $t \geq 0$, its Laplace transform $F(s)$ is defined as $\int_{0}^{\infty }e^{st}f(t)dt \\$ $\int_{0}^{\infty }e^{-st}f(t)dt \\$ $\int_{0}^{\infty }e^{ist}f(t)dt \\$ $\int_{0}^{\infty }e^{-ist}f(t)dt$
Arjun
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Differential Equations
Feb 24, 2017
by
Arjun
27.4k
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gateme-2016-set1
differential-equations
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gatecse
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Differential Equations
Feb 22, 2021
GATE Mechanical 2021 Set 1 | Question: 3
The Dirac-delta function $\left ( \delta \left ( t-t_{0} \right ) \right )$ for $\text{t}$, $t_{0} \in \mathbb{R}$ ... $0$ $\infty$ $e^{sa}$ $e^{-sa}$
gatecse
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Differential Equations
Feb 22, 2021
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gatecse
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gateme-2021-set1
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go_editor
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Differential Equations
Feb 19, 2020
GATE2020-ME-1: 3
The Laplace transform of a function $f(t)$ is $L( f )=\dfrac{1}{(s^{2}+\omega ^{2})}.$ Then, $f(t)$ is $f\left ( t \right )=\dfrac{1}{\omega ^{2}}\left ( 1-\cos\:\omega t \right ) \\$ $f\left ( t \right )=\dfrac{1}{\omega}\cos\:\omega t \\$ $f\left ( t \right )=\dfrac{1}{\omega}\sin\:\omega t \\$ $f\left ( t \right )=\dfrac{1}{\omega^{2}}\left ( 1-\sin\:\omega t \right )$
go_editor
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Differential Equations
Feb 19, 2020
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go_editor
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gateme-2020-set1
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Arjun
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Differential Equations
Feb 24, 2017
GATE2015-3-44
Laplace transform of the function $f(t)$ is given by $F(s)=L\begin{bmatrix} f(t) \end{bmatrix}=\int_{0}^{\infty }f(t)e^{-st}dt$ . Laplace transform of the function shown below is given by $\displaystyle{\frac{1-e^{-2s}}{s}} \\$ $\displaystyle{\frac{1-e^{-s}}{2s}} \\$ $\displaystyle{\frac{2-2e^{-s}}{s}} \\$ $\displaystyle{\frac{1-2e^{-s}}{s}}$
Arjun
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Differential Equations
Feb 24, 2017
by
Arjun
27.4k
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gateme-2015-set3
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