0 votes 0 votes $\displaystyle{}\lim_{x\rightarrow 0}\dfrac{\log_e(1+4x)}{e^{3x}-1}$ is equal to $0 \\$ $\dfrac{1}{12} \\$ $\dfrac{4}{3} \\$ $1$ Calculus gateme-2016-set3 calculus limits + – Arjun asked Feb 24, 2017 • recategorized Mar 5, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply