# GATE2016-3-2

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$\displaystyle{}\lim_{x\rightarrow 0}\dfrac{\log_e(1+4x)}{e^{3x}-1}$ is equal to

1. $0 \\$
2. $\dfrac{1}{12} \\$
3. $\dfrac{4}{3} \\$
4. $1$
in Calculus
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Answer:

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