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asked
in Differential Equations
Feb 19, 2020
recategorized
Mar 6, 2021
by Lakshman Patel RJIT

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The Laplace transform of a function $f(t)$ is $L( f )=\dfrac{1}{(s^{2}+\omega ^{2})}.$ Then, $f(t)$ is

- $f\left ( t \right )=\dfrac{1}{\omega ^{2}}\left ( 1-\cos\:\omega t \right ) \\$
- $f\left ( t \right )=\dfrac{1}{\omega}\cos\:\omega t \\$
- $f\left ( t \right )=\dfrac{1}{\omega}\sin\:\omega t \\$
- $f\left ( t \right )=\dfrac{1}{\omega^{2}}\left ( 1-\sin\:\omega t \right )$