0 0 votes Consider the following partial differential equation for $u(x, y)$, with the constant $c > 1$: $\dfrac{\partial u}{\partial y}+c\dfrac{\partial u}{\partial x}=0$ Solution of this equation is $u(x, y) = f (x+cy)$ $u(x, y) = f (x-cy)$ $u(x, y) = f (cx+y)$ $u(x, y) = f (cx-y)$ Differential Equations gateme-2017-set1 differential-equations partial-differential-equation + – ♦Arjun 323 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.