Register

GATE2015-3-44

• recategorized by
0 votes
0 votes

Laplace transform of the function $f(t)$ is given by $F(s)=L\begin{bmatrix} f(t) \end{bmatrix}=\int_{0}^{\infty }f(t)e^{-st}dt$ . Laplace transform of the function shown below is given by

  1. $\displaystyle{\frac{1-e^{-2s}}{s}} \\$
  2. $\displaystyle{\frac{1-e^{-s}}{2s}} \\$
  3. $\displaystyle{\frac{2-2e^{-s}}{s}} \\$
  4. $\displaystyle{\frac{1-2e^{-s}}{s}}$
• recategorized by
User Avatar

Please log in or register to answer this question.

← PreviousNext →
← Previous in categoryNext in category →
Answer:

Related questions

0 answers
0 votes
Arjun asked Feb 24, 2017
GATE2015-2-4
The Laplace transform of $e^{i5t}$ where $i=\sqrt{-1}$, is $\dfrac{s-5i}{s^2-25} \\$ $\dfrac{s+5i}{s^2+25} \\$ $\dfrac{s+5i}{s^2-25} \\$ $\dfrac{s-5i}{s^2+25} $
The Laplace transform of $e^{i5t}$ where $i=\sqrt{-1}$, is$\dfrac{s-5i}{s^2-25} \\$$\dfrac{s+5i}{s^2+25} \\$$\dfrac{s+5i}{s^2-25} \\$$\dfrac{s-5i}{s^2+25} $
0 answers
0 votes
gatecse asked Feb 22, 2021
GATE Mechanical 2021 Set 1 | Question: 3
The Dirac-delta function $\left ( \delta \left ( t-t_{0} \right ) \right )$ for $\text{t}$, $t_{0} \in \mathbb{R}$ ... $0$ $\infty$ $e^{sa}$ $e^{-sa}$
The Dirac-delta function $\left ( \delta \left ( t-t_{0} \right ) \right )$ for $\text{t}$, $t_{0} \in \mathbb{R}$, has the following property$$\int_{a}^{b}\varphi \left ...
0 answers
0 votes
Arjun asked Feb 24, 2017
GATE2016-3-3
Solutions of Laplace’s equation having continuous second-order partial derivatives are called biharmonic functions harmonic functions conjugate harmonic functions error functions
Solutions of Laplace’s equation having continuous second-order partial derivatives are calledbiharmonic functionsharmonic functionsconjugate harmonic functionserror fun...
0 answers
0 votes
Arjun asked Feb 24, 2017
GATE2016-2-3
Laplace transform of $\cos( \omega t)$ is $\dfrac{s}{s^2+\omega ^2} \\$ $\dfrac{\omega }{s^2+\omega ^2} \\$ $\dfrac{s}{s^2-\omega ^2} \\$ $\dfrac{\omega }{s^2-\omega ^2}$
Laplace transform of $\cos( \omega t)$ is$\dfrac{s}{s^2+\omega ^2} \\$$\dfrac{\omega }{s^2+\omega ^2} \\$$\dfrac{s}{s^2-\omega ^2} \\$$\dfrac{\omega }{s^2-\omega ^2}$
Voting & Accepting an answer helps improve the community
Link Copied!