The solution of $$\dfrac{d^2y}{dt^2}-y=1,$$ which additionally satisfies $y \bigg \vert_{t=0} = \dfrac{dy}{dt} \bigg \vert_{t=0}=0$ in the Laplace $s$-domain is

- $\dfrac{1}{s(s+1)(s-1)} \\$
- $\dfrac{1}{s(s+1)} \\$
- $\dfrac{1}{s(s-1)} \\$
- $\dfrac{1}{s-1} \\$