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Arjun asked Feb 26, 2017
The Laplace transform of $te^{t}$ is$\dfrac{s}{(s+1)^{2}} \\$$\dfrac{1}{(s-1)^{2}} \\$$\dfrac{1}{(s+1)^{2}} \\$$\dfrac{s}{(s-1)}$
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Arjun asked Feb 19, 2017
The solution of the initial value problem $\dfrac{dy}{dx}=-2xy$ ; $y(0)=2$ is$1+e^{{-x}^2}$$2e^{{-x}^2}$$1+e^{{x}^2}$$2e^{{x}^2}$
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Arjun asked Feb 24, 2017
The Laplace transform of $e^{i5t}$ where $i=\sqrt{-1}$, is$\dfrac{s-5i}{s^2-25} \\$$\dfrac{s+5i}{s^2+25} \\$$\dfrac{s+5i}{s^2-25} \\$$\dfrac{s-5i}{s^2+25} $