0 votes 0 votes The Laplace transform of $te^{t}$ is $\dfrac{s}{(s+1)^{2}} \\$ $\dfrac{1}{(s-1)^{2}} \\$ $\dfrac{1}{(s+1)^{2}} \\$ $\dfrac{s}{(s-1)}$ Differential Equations gateme-2017-set2 differential-equations laplace-transforms + – Arjun asked Feb 26, 2017 • recategorized Mar 5, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply