0 votes 0 votes The value of the integral $$\int_{0}^{2}\dfrac{(x-1)^2\sin(x-1)}{(x-1)^2+\cos(x-1)}dx$$ is $3$ $0$ $-1$ $-2$ Calculus gateme-2014-set4 calculus definite-integrals + – Arjun asked Feb 19, 2017 • recategorized Mar 4, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply