0 0 votes The value of the integral $$\int_{0}^{2}\dfrac{(x-1)^2\sin(x-1)}{(x-1)^2+\cos(x-1)}dx$$ is $3$ $0$ $-1$ $-2$ Calculus gateme-2014-set4 calculus definite-integrals + – ♦Arjun 272 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.