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Recent questions tagged area-under-curve

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GATE2019 ME-1: 2
A parabola $x=y^2$ with $0 \leq x \leq 1$ is shown in the figure. The volume of the solid of rotation obtained by rotating the shaded area by $360^{\circ}$ around x-axis is $\dfrac{\pi}{4} \\$ $\dfrac{\pi}{2} \\$ ${\pi} \\$ $2 \pi$

Arjun asked in Calculus Feb 9, 2019

by Arjun

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GATE ME 2012 | Question: 11
The area enclosed between the straight line $y=x$ and the parabola $y=x^2$ in the $x-y$ plane is $1/6$ $1/4$ $1/3$ $1/2$

Andrijana3306 asked in Calculus Mar 20, 2018

by Andrijana3306

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GATE2017 ME-1: 28
A parametric curve defined by $x= \cos \left ( \dfrac{\Pi u}{2} \right ), y= \sin \left ( \dfrac{\Pi u}{2} \right )$ in the range $0 \leq u \leq 1$ is rotated about the $X$-axis by $360$ degrees. Area of the surface generated is $\dfrac{\Pi }{2} \\$ $\pi \\$ $2 \pi \\$ $4 \pi$

Arjun asked in Calculus Feb 27, 2017

by Arjun

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GATE2015-2-27
The surface integral $\displaystyle{} \int \int_{s}^{ }\dfrac{1}{\pi }(9xi-3yj)\cdot nds$ over the sphere given by $x^2+y^2+z^2=9$ is

Arjun asked in Calculus Feb 24, 2017

by Arjun

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GATE Mechanical 2014 Set 1 | Question: 26
The integral $\oint_{c}^{ } (ydx-xdy)$ is evaluated along the circle $x^2+y^2=\frac{1}{4}$ traversed in counter clockwise direction. The integral is equal to $0$ $\frac{-\pi }{4}$ $\frac{-\pi }{2}$ $\frac{\pi }{4}$

Arjun asked in Calculus Feb 19, 2017

by Arjun

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GATE ME 2013 | Question: 26
The following surface integral is to be evaluated over a sphere for the given steady velocity vector field $F$ = $xi$ + $yj$+ $zk$ defined with respect to a Cartesian coordinate system having $i$, $j$ and $k$ ... is the outward unit normal vector to the sphere. The value of the surface integral is $\pi$ $2\pi$ $3\pi/4$ $4\pi$

piyag476 asked in Calculus Feb 19, 2017

1.4k points

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