0 votes 0 votes The solution of the initial value problem $\dfrac{dy}{dx}=-2xy$ ; $y(0)=2$ is $1+e^{{-x}^2}$ $2e^{{-x}^2}$ $1+e^{{x}^2}$ $2e^{{x}^2}$ Differential Equations gateme-2014-set4 differential-equations + – Arjun asked Feb 19, 2017 • recategorized Mar 4, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply