The velocity field of a two-dimensional, incompressible flow is given by
\[
\vec{V}=2 \sinh x \hat{\imath}+v(x, y) \hat{\jmath}
\]
where $\hat{\imath}$ and $\hat{\jmath}$ denote the unit vectors in $x$ and $y$ directions, respectively. If $v(x, 0)=\cosh x$, then $v(0,-1)$ is
- $1$
- $2$
- $3$
- $4$