3 3 votes Find the odd one out in the set: $\{19,37,21,17,23,29,31,11\}$ $21$ $29$ $37$ $23$ Analytical Aptitude gateme-2024 analytical-aptitude odd-one easy + – ♦admin 3.6k views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
0 0 votes Correct answer is Option A) remaining all are Prime numbers, just 21 is not prime, factors are 1,3,7,21. aap33 answered Feb 18, 2024 • moved May 9 by Shubham Sharma 2 aap33 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes 21 is the odd one in the set as all other numbers 19,37,17,23,19,31,11 are prime numbers . Which means all the numbers except 21 has only two divisors, 1 and that number itself. But 21=7x3 which means 21 is a composite number and has 4 divisors (1,3,7,21). sujayangupta answered Sep 20, 2024 • moved May 9 by Shubham Sharma 2 sujayangupta comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes FROM THE ABOVE CONDITION....EXCEPT 21, ALL NUMBER ARE PRIME NUMBER SO, CORRECT ANSWER IS OPTION (A) shekharjaideep answered Sep 27, 2025 • moved May 9 by Shubham Sharma 2 shekharjaideep comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes A Bhavani 1 answered Oct 1, 2025 • moved May 9 by Shubham Sharma 2 Bhavani 1 comment Share Follow 0 reply Please log in or register to add a comment.
–1 –1 vote A remaining all are Prime numbers, just 21 is not prime, factors are 1,3,7,21. aap33 answered Feb 18, 2024 aap33 comment Share Follow 0 reply Please log in or register to add a comment.