edited by
0 votes
0 votes

​​The real variables $x, y, z$, and the real constants $p, q, r$ satisfy

\[
\frac{x}{p q-r^{2}}=\frac{y}{q r-p^{2}}=\frac{z}{r p-q^{2}}
\]

Given that the denominators are non-zero, the value of $p x+q y+r z$ is

  1. $0$
  2. $1$
  3. $p q r$
  4. $p^{2}+q^{2}+r^{2}$
edited by

Please log in or register to answer this question.

Answer:

Related questions

1 answers
1 votes
admin asked Feb 16
​​​Find the odd one out in the set: $\{19,37,21,17,23,29,31,11\}$$21$$29$$37$$23$
0 answers
0 votes
admin asked Feb 16
​​​​​In the following series, identify the number that needs to be changed to form the Fibonacci series.$1,1,2,3,6,8,13,21, \ldots$$8$$21$$6$$13$