0 votes 0 votes One kg of air ($R=287 \: J/kg – K$) undergoes an irreversible process between equilibrium state $1(20^{\circ}C$, $0.9 \: m^3$) and equilibrium state $2 ( 20^{\circ} C$, $0.6\: m^3$). The change in entropy $s_2 – s_1$ (in $J/kg – K$) is _______ Applications gateme-2015-set2 numerical-answers applications fluid-mechanics-and-thermal-science + – Arjun asked Feb 24, 2017 • recategorized Mar 4, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply