1 1 vote If a positive real $x$ satisfies the following equation\[\log _{2} x+\log _{\sqrt{2}} x=48,\]then the value of $x$ is $\_\_\_\_$$2^{16}$$4^{16}$$2^{14}$$4^{14}$ Analytical Aptitude gateme-2026 quantitative-aptitude numerical-answers + – ♦gatecse 308 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
0 0 votes x = 2 raised to the power 16 so option A akash_kumar 9 answered Mar 10 akash_kumar 9 comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes You Can Solve it by putting Option Directly and you will get the answers but if it's Would NAT type then Prashant-G answered May 11 Prashant-G comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Much Better Solution then Previous one Prashant-G answered May 11 Prashant-G comment Share Follow 0 reply Please log in or register to add a comment.
