0 votes 0 votes The value of the surface integral $\oiint_{S} z d x d y$ where $S$ is the external surface of the sphere $x^{2}+y^{2}+z^{2}=R^{2}$ is $0$ $4 \pi R^{3}$ $\frac{4 \pi}{3} R^{3}$ $\pi R^{3}$ Others gateme-2024 + – admin asked Feb 16 • edited Feb 23 by makhdoom ghaya ♦admin 4.4k points answer See all 0 reply