The change in kinetic energy $\Delta E$ of an engine is $300 \mathrm{~J}$, and minimum and maximum shaft speeds are $\omega_{\min }=220 \mathrm{rad} / \mathrm{s}$ and $\omega_{\max }=280 \mathrm{rad} / \mathrm{s}$, respectively. Assume that the torque-time function is purely harmonic. To achieve a coefficient of fluctuation of $0.05$, the moment of inertia (in $\mathrm{kg} \cdot \mathrm{m}^{2}$ ) of the flywheel to be mounted on the engine shaft is
- $0.113$
- $0.096$
- $0.071$
- $0.053$