If the Laplace transform of a function $f(t)$ is given by $\frac{s+3}{\left ( s+1 \right )\left ( s+2 \right )}$, then $f(0)$ is

1. $0$
2. $\frac{1}{2}$
3. $1$
4. $\frac{3}{2}$

Apply Intitial Value theorem

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