recategorized by
299 views
0 0 votes

The function $f(z)$ of complex variable $z=x+iy$, where $i=\sqrt{-1}$, is given as $f(z)=(x^3-3xy^2)+i \: v(x,y)$. For this function to be analytic, $v(x,y)$ should be

  1. $(3xy^2-y^3) +$ constant
  2. $(3x^2y^2-y^3) +$ constant
  3. $(x^3-3x^2 y) +$ constant
  4. $(3x^2y-y^3) +$ constant

Please log in or register to answer this question.

Related questions

0 0 votes
0 0 answers
308
308 views
go_editor asked Feb 19, 2020
308 views
An analytic function of a complex variable $z=x + iy \left ( i=\sqrt{-1} \right )$ is defined as$$f\left ( z \right )=x^{2}-y^{2}+i\psi \left ( x,y \right ),$$where $\psi...
0 0 votes
1 1 answer
699
699 views
Arjun asked Feb 9, 2019
699 views
An analytic function $f(z)$ of complex variable $z=x+iy$ may be written as $f(z)=u(x,y)+iv(x,y)$. Then $u(x,y)$ and $v(x,y)$ must satisfy$\dfrac{\partial u}{ \partial x} ...
0 0 votes
0 0 answers
318
318 views
gatecse asked Feb 22, 2021
318 views
Let $\text{C}$ represent the unit circle centered at origin in the complex plane, and complex variable, $z=x+iy$. The value of the contour integral $\oint _{C}\dfrac{\cos...
0 0 votes
0 0 answers
381
381 views
go_editor asked Sep 18, 2020
381 views
Let $I=\displaystyle \int_{x=0}^1 \int_{y=0}^{x^2} xy^2 dy \: dx$. Then, $I$ may also be expressed as$\displaystyle \int_{y=0}^1 \int_{x=0}^{\sqrt{y}} xy^2 dx \: dy$$\dis...

Related questions

0 0 votes
0 0 answers
308
308 views
go_editor asked Feb 19, 2020
308 views
An analytic function of a complex variable $z=x + iy \left ( i=\sqrt{-1} \right )$ is defined as$$f\left ( z \right )=x^{2}-y^{2}+i\psi \left ( x,y \right ),$$where $\psi...
0 0 votes
1 1 answer
699
699 views
Arjun asked Feb 9, 2019
699 views
An analytic function $f(z)$ of complex variable $z=x+iy$ may be written as $f(z)=u(x,y)+iv(x,y)$. Then $u(x,y)$ and $v(x,y)$ must satisfy$\dfrac{\partial u}{ \partial x} ...
0 0 votes
0 0 answers
318
318 views
gatecse asked Feb 22, 2021
318 views
Let $\text{C}$ represent the unit circle centered at origin in the complex plane, and complex variable, $z=x+iy$. The value of the contour integral $\oint _{C}\dfrac{\cos...
0 0 votes
0 0 answers
381
381 views
go_editor asked Sep 18, 2020
381 views
Let $I=\displaystyle \int_{x=0}^1 \int_{y=0}^{x^2} xy^2 dy \: dx$. Then, $I$ may also be expressed as$\displaystyle \int_{y=0}^1 \int_{x=0}^{\sqrt{y}} xy^2 dx \: dy$$\dis...
Position:
Show:
Answer:

Add Synced Question

×