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A plan slab of thickness $L$ and thermal conductivity $k$ is heated heated with a fluid on one side $(P)$, and the other side (Q) is maintained at a constant temperature, $T_Q$ of $25^oC$, as shown in the figure, the fluid is at $45^oC$ and the surface heat transfer coefficient, $h$, is $10 \: W/m^2K$. The steady state temperature, $T_P$ (in $^oC) of the side which is exposed to the fluid is _____ (correct to two decimal places) edited ## 1 Answer 0 votes$Q = \Delta T / Thermal Resistance\$

(45-Tp)/(1/10) = (45-25) / ((1/10)+(0.2/2.5))

Tp=33.89
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