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We can use Binomial Distribution to solve this question.

  • P (obtaining ONE at least four times) = P (X=4 or X=5) 

 

  • Here, Success = p = obtaining one = 1/6 and failure = q = not obtaining one = 5/6, n = 5,

 

  • P (X=4 or X=5) = 5c4 x (1/6)^4 x (5/6)^1 + 5c5 x (1/6)^5 x (5/6)^0

         =    0.0033

  • Hence, in percentage (%) = 0.33% ........ ( 0.0033 x 100 )

 

  • Therefore, Option C  i.e. 0.33 would be correct answer.

 

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