recategorized by

Please log in or register to answer this question.

Answer:

Related questions

0 answers
0 votes
Arjun asked Feb 19, 2017
$ \displaystyle{}\lim_{x\rightarrow 0} \left( \dfrac{e^{2x}-1}{\sin(4x)} \right )$ is equal to$0$$0.5$$1$$2$
0 answers
0 votes
gatecse asked Feb 22, 2021
The value of $\displaystyle{} \lim_{x \rightarrow 0} \left( \frac{1 – \cos x}{x^{2}}\right)$ is$\frac{1}{4}$$\frac{1}{3}$$\frac{1}{2}$$1$
0 answers
0 votes
go_editor asked Feb 19, 2020
The value of $\displaystyle{}\lim_{x \to \infty}\left ( \dfrac{1 -e^{-c\left ( 1-x \right )}}{1-x\:e^{-c\left ( 1-x \right )}} \right )$ is$\text{c} \\$$\text{c + 1} \\$$...
0 answers
0 votes
Arjun asked Feb 26, 2017
The value of $\displaystyle{}\lim_{x \rightarrow 0}\dfrac{x^{3}-\sin(x)}{x}$ is$0$$3$$1$$-1$