0 votes 0 votes The value of the definite integral $\int_{1}^{e}\sqrt{x}\ln(x)dx$ is $\dfrac{4}{9}\sqrt{e^3}+\dfrac{2}{9} \\$ $\dfrac{2}{9}\sqrt{e^3}-\dfrac{4}{9} \\$ $\dfrac{2}{9}\sqrt{e^3}+\dfrac{4}{9}\\$ $\dfrac{4}{9}\sqrt{e^3}-\dfrac{2}{9}$ Calculus gateme-2013 calculus definite-integrals + – piyag476 asked Feb 19, 2017 recategorized Mar 3, 2021 by Lakshman Bhaiya piyag476 1.4k points 4 42 68 answer See all 0 reply