0 votes 0 votes For the situation shown in the figure below the expression for $H$ in terms of $r$, $R$ and $D$ is $H=D+\sqrt{r^2+R^2}$ $H=(R+r)+(D+r)$ $H=(R+r)+\sqrt{D^2-R^2}$ $H=(R+r)+\sqrt{2D(R+r)-D^2}$ Fluid Mechanics gateme-2016-set2 fluid-mechanics + – Arjun asked Feb 24, 2017 recategorized Mar 5, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply