0 0 votes For the situation shown in the figure below the expression for $H$ in terms of $r$, $R$ and $D$ is $H=D+\sqrt{r^2+R^2}$ $H=(R+r)+(D+r)$ $H=(R+r)+\sqrt{D^2-R^2}$ $H=(R+r)+\sqrt{2D(R+r)-D^2}$ Fluid Mechanics gateme-2016-set2 fluid-mechanics + – ♦Arjun 323 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.