recategorized by
0 votes
0 votes

$f(z)=u(x,y)+iv(x,y)$ is an analytic function of complex variable $z=x+iy$ where $i=\sqrt{-1}$. If $u(x,y)$=$2xy$ , then $v(x,y)$ may be expressed as

  1. $-x^2 + y^2 + $ constant
  2. $x^2 – y^2 +$ constant
  3. $x^2 + y^2 +$ constant
  4. $-(x^2 + y^2) +$ constant
recategorized by

Please log in or register to answer this question.

Answer:

Related questions

0 answers
0 votes
Arjun asked Feb 19, 2017
The argument of the complex number $\dfrac{1+\imath }{1-\imath }$ where $\imath =\sqrt{-1}$ ,is$-\pi \\$$\dfrac{-\pi }{2} \\$$\dfrac{\pi }{2} \\$ $\pi$
0 answers
0 votes
Arjun asked Feb 24, 2017
A function of the complex variable $z= x+iy$, is given as $f(x,y) =u(x,y) +iv(x,y)$ , where $u(x,y) = 2kxy$ and $ v(x,y) =x^2 −y^2$. The value of $k$, for which the fun...
0 answers
0 votes
Arjun asked Feb 24, 2017
If $y=f(x)$ satisfies the boundary value problem ${y}''+9y=0$ , $y(0)=0$ , $y(\pi /2)=\sqrt{2}$, then $y(\pi /4)$ is ________