recategorized by
0 votes
0 votes

For flow through a pipe of radius $R$, the velocity and temperature distribution are as follows:
$u(r,x)=C_1,$, and $T(r,x)=C_2[1- \left (\dfrac{r}{R} \right )^3]$ where $C_1$ and $C_2$ are constants. The bulk mean  temperature is given by $T_m=\dfrac{2}{U_mR^2}\int_{0}^{R}u(r,x)T(r,x)rdr$, with $U_m$ being the mean velocity of flow. The value of $T_m$ is

  1. $\dfrac{0.5C_2}{U_m} \\$
  2. $0.5C_2 \\$
  3. $0.6C_2 \\$
  4. $\dfrac{0.6C_2}{U_m}$
recategorized by

Please log in or register to answer this question.

Answer:

Related questions

0 answers
0 votes
Arjun asked Feb 24, 2017
A swimmer can swim $10$ $km$ in $2$ hours when swimming along the flow of a river. While swimming against the flow, she takes $5$ hours for the same distance. Her speed i...