0 0 votes Take two long dice (rectangular parallelepiped), each having four rectangular faces labelled as $2,3,5$, and $7$. If thrown, the long dice cannot land on the square faces and has $1 / 4$ probability of landing on any of the four rectangular faces. The label on the top face of the dice is the score of the throw. If thrown together, what is the probability of getting the sum of the two long dice scores greater than $11$? $3 / 8$ $1 / 8$ $1 / 16$ $3 / 16$ Quantitative Aptitude gateme-2024 quantitative-aptitude probability + – ♦admin 1.9k views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
0 0 votes The Correct Answer is Option B) 1/8 . We have total 16 possible outcomes out of which only two are favourable outcomes that is (5,7) , (7,5) . So , the required probablity is 2/16 which is 1/8. Thadymademe answered Aug 7, 2024 • moved May 9 by Shubham Sharma 2 1 flag: ✌ Edit necessary (narainkaarthik “not taking all cases”) Thadymademe comment Share Follow See 1 comment 1 1 comment reply Rohit_Singh 9 commented Aug 25 reply Follow flag @Thadymademe You missed the one favourable outcome which is (7,7). 0 0 replyShare Please log in or register to add a comment.
0 0 votes There are 3 possibilities: 5,7 or 7,5 or 7,7 So the overall probability=3*(1/4)*(1/4)=3/16 Option D) Murad Aalam answered Dec 28, 2024 Murad Aalam comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Solution 3/16 Bhargobi answered Jan 14, 2025 • moved May 9 by Shubham Sharma 2 Bhargobi comment Share Follow 0 reply Please log in or register to add a comment.
0 0 votes Two Dice with 4 faces , Sample space = 4*4 .= 16. Favourable cases for scores greater than 11 = (5,7) , (7,7) , (7,5). = 3 Hence the answer would be 3/16. Pbhagya answered Apr 14, 2025 • moved May 9 by Shubham Sharma 2 Pbhagya comment Share Follow 0 reply Please log in or register to add a comment.