0 0 votes Which one of the options given is the inverse Laplace transform of $\frac{1}{s^3-S} ?$ $u(t)$ denotes the unit-step function. $\left(-1+\frac{1}{2} e^{-t}+\frac{1}{2} e^t\right) u(t)$ $\left(\frac{1}{3} e^{-t}-e^t\right) u(t)$ $\left(-1+\frac{1}{2} e^{-(t-1)}+\frac{1}{2} e^{(t-1)}\right) u(t-1)$ $\left(-1-\frac{1}{2} e^{-(t-1)}-\frac{1}{2} e^{(t-1)}\right) u(t-1)$ Differential Equations gateme-2023 laplace-transforms engineering-mathematics + – ♦admin 1.1k views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.