0 0 votes A cylindrical rod of length $h$ and diameter $d$ is placed inside a cubic enclosure of side length $L. S$ denotes the inner surface of the cube. The view-factor $F_{S-S}$ is $0$ $1$ $\frac{\left(\pi d h+\pi d^2 / 2\right)}{6 L^2}$ $1-\frac{\left(\pi d h+\pi d^2 / 2\right)}{6 L^2}$ Heat Transfer gateme-2023 heat-transfer view-factors engineering-mechanics + – ♦admin 396 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
