0 0 votes A car having weight $W$ is moving in the direction as shown in the figure. The center of gravity (CG) of the car is located at height $h$ from the ground, midway between the front and rear wheels. The distance between front and rear wheel is $l$. The acceleration of the car is $a$, and acceleration due to gravity is $g$. The reactions on the front wheels $(R_f)$ and rear wheels $(R_r)$ are given by $R_f=R_r = \dfrac{W}{2}-\frac{W}{g} \bigg( \dfrac{h}{l} \bigg) a \\$ $R_f= \dfrac{W}{2}+\dfrac{W}{g} \bigg( \dfrac{h}{l} \bigg) a ; R_r = \dfrac{W}{2}-\dfrac{W}{g} \bigg( \dfrac{h}{l} \bigg) a \\ $ $R_f= \dfrac{W}{2}-\dfrac{W}{g} \bigg( \dfrac{h}{l} \bigg) a ; R_r = \dfrac{W}{2}+\dfrac{W}{g} \bigg( \dfrac{h}{l} \bigg) a \\$ $R_f=R_r = \dfrac{W}{2}+\dfrac{W}{g} \bigg( \dfrac{h}{l} \bigg) a$ Theory of Machines gateme-2019-set1 theory-of-machines applied-mechanics-and-design + – ♦Arjun 765 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
