A solid disc of radius $r$ rolls without slipping on a horizontal floor with angular velocity $\omega$ and angular acceleration $\alpha$. The magnitude of the acceleration of the point of contract on the disc is

1. $zero$
2. $r \alpha$
3. $\sqrt{(r \alpha)^2 + (r \omega^2)^2}$
4. $r \omega^2$

Answer:

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