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GATE ME 2012 | Question: 35
Andrijana3306
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Mar 20, 2018
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The inverse Laplace transform of the function $F(s) = \dfrac{1}{s(s+1)}$ is given by
$f(t) = \sin t$
$f(t) = e^{-t} \sin t$
$f(t) = e^{-t}$
$f(t) = 1-e^{-t}$
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