Consider two infinitely long thin concentric tubes of circular cross section as shown in the figure. If $D_1$ and $D_2$ are the diameters of the inner and outer tubes respectively, then the view factor $F_{22}$ is given by
- $\bigg( \dfrac{D_1}{D_2} \bigg) -1 \\$
- $\text{zero} \\$
- $\bigg( \dfrac{D_1}{D_2} \bigg) \\$
- $1- \bigg( \dfrac{D_1}{D_2} \bigg)$