0 0 votes Consider two infinitely long thin concentric tubes of circular cross section as shown in the figure. If $D_1$ and $D_2$ are the diameters of the inner and outer tubes respectively, then the view factor $F_{22}$ is given by $\bigg( \dfrac{D_1}{D_2} \bigg) -1 \\$ $\text{zero} \\$ $\bigg( \dfrac{D_1}{D_2} \bigg) \\$ $1- \bigg( \dfrac{D_1}{D_2} \bigg)$ Fluid Mechanics gateme-2012 fluid-mechanics-and-thermal-science + – Andrijana3306 450 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.