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Consider two infinitely long thin concentric tubes of circular cross section as shown in the figure. If $D_1$ and $D_2$ are the diameters of the inner and outer tubes respectively, then the view factor $F_{22}$ is given by

  1. $\bigg( \dfrac{D_1}{D_2} \bigg) -1 \\$
  2. $\text{zero} \\$
  3. $\bigg( \dfrac{D_1}{D_2} \bigg) \\$
  4. $1- \bigg( \dfrac{D_1}{D_2} \bigg)$
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