0 0 votes An ideal gas of mass $m$ and temperature $T_1$ undergoes a reversible isothermal process from an initial pressure $P_1$ to final pressure $P_2$. The hear loss during the process is $Q$. The entropy change $\Delta S$ of the gas is $mR \: \ln \bigg( \dfrac{P_2}{P_1} \bigg) \\$ $mR \: \ln \bigg( \dfrac{P_1}{P_2} \bigg) \\$ $mR \: \ln \bigg( \dfrac{P_2}{P_1} \bigg) - \dfrac{Q}{T_1} \\$ $\text{zero}$ Fluid Mechanics gateme-2012 fluid-mechanics-and-thermal-science fluid-mechanics + – Andrijana3306 290 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.
