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GATE2018-2-36
Arjun
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Differential Equations
Feb 17, 2018
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Mar 5, 2021
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Lakshman Patel RJIT
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Given the ordinary differential equation $$\dfrac{d^2y}{dx^2}+\dfrac{dy}{dx}-6y=0$$ with $y(0)=0$ and $\dfrac{dy}{dx}(0)=1$, the value of $y(1)$ is __________ (correct to two decimal places).
gateme-2018-set2
numerical-answers
differential-equations
Arjun
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Differential Equations
Feb 17, 2018
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Mar 5, 2021
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Lakshman Patel RJIT
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Answer:
1.45 : 1.48
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