0 votes 0 votes Given the ordinary differential equation $$\dfrac{d^2y}{dx^2}+\dfrac{dy}{dx}-6y=0$$ with $y(0)=0$ and $\dfrac{dy}{dx}(0)=1$, the value of $y(1)$ is __________ (correct to two decimal places). Differential Equations gateme-2018-set2 numerical-answers differential-equations + – Arjun asked Feb 17, 2018 • retagged Mar 5, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply