0 0 votes A solid steel cube constrained on all six faces is heated so that the temperature rises uniformly by $\Delta T$. If the thermal coefficient of the material is $\alpha$, Young's modulus is $E$ and the Poisson's ratio is $\upsilon$, the thermal stress developed in the cube due to heating is $-\dfrac{\alpha (\Delta T) E}{(1-2 \upsilon)} \\$ $-\dfrac{2 \alpha (\Delta T) E}{(1-2 \upsilon)} \\$ $-\dfrac{3 \alpha (\Delta T) E}{(1-2 \upsilon)} \\$ $-\dfrac{\alpha (\Delta T) E}{3 (1-2 \upsilon)}$ Heat Transfer gateme-2012 fluid-mechanics-and-thermal-science heat-transfer + – Andrijana3306 522 views answer comment Share Follow Add Sync Questions 0 reply Please log in or register to add a comment.