Recent activity in Differential Equations

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The Dirac-delta function $\left ( \delta \left ( t-t_{0} \right ) \right )$ for $\text{t}$, $t_{0} \in \mathbb{R}$, has the following property$$\int_{a}^{b}\varphi \left ...
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The ordinary differential equation $\dfrac{dy}{dt}=-\pi y$ subject to an initial condition $y\left ( 0 \right )=1$ is solved numerically using the following scheme:$$\fra...
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The differential equation $\dfrac{dy}{dx}+4y=5$ is valid in the domain $0 \leq x \leq 1$ with $y(0)=2.25$. The solution of the differential equation is$y=e^{-4x}+5$$y=e^{...
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For the equation $\dfrac{dy}{dx}+7x^2y=0$, if $y(0)=3/7$, then the value of $y(1)$ is$\dfrac{7}{3}e^{-7/3} \\$$\dfrac{7}{3}e^{-3/7} \\$$\dfrac{3}{7}e^{-7/3} \\$$\dfrac{3}...
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If $y$ is the solution of the differential equation $y^3 \dfrac{dy}{dx}+x^3 = 0, \: y(0)=1,$ the value of $y(-1)$ is$-2$$-1$$0$$1$
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Given the ordinary differential equation $$\dfrac{d^2y}{dx^2}+\dfrac{dy}{dx}-6y=0$$ with $y(0)=0$ and $\dfrac{dy}{dx}(0)=1$, the value of $y(1)$ is __________ (correct to...
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$F(s)$ is the Laplace transform of the function $f(t) =2t^2 e^{-t}$. $F(1)$ is _______ (correct to two decimal places).
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Consider the differential equation $3y" (x)+27 y (x)=0$ with initial conditions $y(0)=0$ and $y'(0)=2000$. The value of $y$ at $x=1$ is ________.
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The Laplace transform of $te^{t}$ is$\dfrac{s}{(s+1)^{2}} \\$$\dfrac{1}{(s-1)^{2}} \\$$\dfrac{1}{(s+1)^{2}} \\$$\dfrac{s}{(s-1)}$
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Solutions of Laplace’s equation having continuous second-order partial derivatives are calledbiharmonic functionsharmonic functionsconjugate harmonic functionserror fun...
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Laplace transform of $\cos( \omega t)$ is$\dfrac{s}{s^2+\omega ^2} \\$$\dfrac{\omega }{s^2+\omega ^2} \\$$\dfrac{s}{s^2-\omega ^2} \\$$\dfrac{\omega }{s^2-\omega ^2}$
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Consider the following differential equation:$\dfrac{dy}{dt}=-5y$; initial condition: $y=2$ at $t=0$. The value of $y$ at $t=3$ is$-5e^{-10}$$2e^{-10}$$2e^{-15}$$-15e^...
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The Laplace transform of $e^{i5t}$ where $i=\sqrt{-1}$, is$\dfrac{s-5i}{s^2-25} \\$$\dfrac{s+5i}{s^2+25} \\$$\dfrac{s+5i}{s^2-25} \\$$\dfrac{s-5i}{s^2+25} $
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The solution of the initial value problem $\dfrac{dy}{dx}=-2xy$ ; $y(0)=2$ is$1+e^{{-x}^2}$$2e^{{-x}^2}$$1+e^{{x}^2}$$2e^{{x}^2}$
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