in Theory of Machines edited by
0 votes
0 votes

In a cam-follower, the follower rises by $h$ as the cam rotates by $\delta$ (radians) at constant angular velocity $\omega$ (radians/s). The follower is uniformly accelerating during the first half of the rise period and it is uniformly decelerating in the latter half of the rise period. Assuming that the magnitudes of the acceleration and declaration are same, the maximum velocity of the follower is

  1. $\dfrac{4h \omega}{\delta} \\$
  2. $h \omega \\$
  3. $\dfrac{2h \omega}{\delta} \\$
  4. $2h \omega$
in Theory of Machines edited by
27.4k points

Please log in or register to answer this question.


Related questions