In a power plant, water (density = $1000$ $kg$/$m^3$) is pumped from $80$ $kPa$ to $3$ $MPa$. The pump has an isentropic efficiency of $0.85$. Assuming that the temperature of the water remains the same, the specific work (in $kJ$/$kg$) supplied to the pump is
- $0.34$
- $2.48$
- $2.92$
- $3.43$