In the assembly shown below, the part dimensions are:
$L_1 = 22.0^{\pm 0.01} \: mm$,
$L_2 = L_3$ = $10.0^{\pm 0.005} \: mm$.
Assuming the normal distribution of part dimensions, the dimension $L_4$ in $mm$ for assembly condition would be:
- $2 .0^{\pm 0.008}$
- $2 .0^{\pm 0.012}$
- $2 .0^{\pm 0.016}$
- $2 .0^{\pm 0.020}$