0 votes 0 votes Holes of diameter $25.0^{{+0.020} \\ {+0.040}}$ $mm$ are assembled interchangeably with the pins of diameter $25.0^{{+0.008}\\{+0.005}}$ $mm$. The minimum clearance in the assembly will be $0.048$ $mm$ $0.015$ $mm$ $0.005$ $mm$ $0.008$ $mm$ Materials, Manufacturing and Industrial Engineering gateme-2015-set1 materials-manufacturing-and-industrial-engineering metrology-and-inspection limits + – Arjun asked Feb 24, 2017 • recategorized Mar 4, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply