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Holes of diameter $25.0^{{+0.020} \\ {+0.040}}$ $mm$ are assembled interchangeably with the pins of diameter $25.0^{{+0.008}\\{+0.005}}$ $mm$. The minimum clearance in the assembly will be

  1. $0.048$ $mm$
  2. $0.015$ $mm$
  3. $0.005$ $mm$
  4. $0.008$ $mm$
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