0 votes 0 votes Laplace transform of $\cos(\omega t)$ is $\dfrac{s}{s^2+\omega ^2}$. The Laplace transform of $e^{-2t} \cos(4t)$ is $\dfrac{s-2}{(s-2)^2+16} \\$ $\dfrac{s+2}{(s-2)^2+16} \\$ $\dfrac{s-2}{(s+2)^2+16} \\$ $\dfrac{s+2}{(s+2)^2+16}$ Differential Equations gateme-2014-set4 differential-equations laplace-transforms + – Arjun asked Feb 19, 2017 • recategorized Mar 4, 2021 by Lakshman Bhaiya ♦Arjun 28.5k points answer See all 0 reply