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Given that$,2 - 5x \leq -\; \frac{6x - 5}{3}$

$\Rightarrow 6 – 15x \leq -6x + 5$

$\Rightarrow 6 – 5 \leq -6x + 15x $

$\Rightarrow 1 \leq 9x$

$\Rightarrow {\color{Blue} {\boxed{x \geq \frac{1}{9}}}}$

Correct Answer $:\text{C}$
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