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The vector function expressed by 

                  $F= a_{x}(5y-k_{1}z)+a_{y}(3z+k_{2}x)+a_{z}(k_{3}y-4x)$

represents a conservative field, where $a_{x},a_{y},a_{z}$ are unit vectors along $x,y$ and $z$ directions, respectively. The values of constants $k_{1},k_{2},k_{3}$ are given by:

  1. $k_{1}= 3,k_{2}= 3,k_{3}= 7$
  2. $k_{1}= 3,k_{2}= 8,k_{3}= 5$
  3. $k_{1}= 4,k_{2}= 5,k_{3}= 3$
  4. $k_{1}= 0,k_{2}= 0,k_{3}= 0$
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