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asked
in Applied Mechanics and Design
Feb 19, 2020
recategorized
Mar 6, 2021
by Lakshman Patel RJIT

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A single-degree-of-freedom oscillator is subjected to harmonic excitation $F(t) = F_{0}\cos(\omega t)$ as shown in the figure.

The non-zero value of $\omega$, for which the amplitude of the force transmitted to the ground will be $F_{0}$, is

- $\sqrt{\dfrac{k}{2m}} \\$
- $\sqrt{\dfrac{k}{m}} \\$
- $\sqrt{\dfrac{2k}{m}} \\$
- $2\sqrt{\dfrac{k}{m}}$